PROCEDURE & CRITERIA FOR DECLARATION OF RESULT: CBSE NET December 2015
This will comprise of following steps:
Step I: Minimum marks to be obtained in NET for considering a candidate for the award of JRF and eligibility for Assistant Professor:
The candidates are required to obtain minimum marks separately in Paper-I, Paper-II and Paper –III as given below
Step II: Amongst those candidates who have cleared step I, a merit list will be prepare subject-wise and category-wise using the aggregate marks of all the three papers secured by such candidates.
| CATEGORY | Minimum Marks (%) to be obtained | ||
| PAPER – I | PAPER – II | PAPER – II | |
| GENERAL | 40 (40%) | 40(40%) | 75 (50%) |
| OBC (Non-creamy layer) PWD/SC/ST | 35 (35%) | 35 (35%) | 60 (40%) |
Step III: Top 15% candidates (for each subject and category), from the merit list mentioned under step II, will be declared NET qualified for eligibility for Assistant Professor only.
Step IV: A separate merit list for the award of JRF will be prepared from amongst the NET qualified candidates figuring in the merit list prepared under step III.
It may be noted that the above qualifying criteria decided by UGC/CBSE is final and binding.
Click this link to know Cut Off Marks : CBSE UGC NET June 2015 Exam Qualifying Criteria
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